.::VULMSIT::.eNoxel Re: [vumasters] Idea Solution cs609

 see in q=1 u have to do parallel communication b/w 2 PCs... for th8.....as u know ,

we can not send the whole byte from one computer to other,  We can only send the nibble that is of 4 bit length.  So break the given two byte data into nibbles and send it to other computer from lower to higher nibble. There are 4 nibbles in two bytes n also u have to follow the protocol.

i will show u sending of one nibble .u follow the same for remaining........

ur's given data is to transfer 0x3536....

in it u have..

1 nibble for hex 3=0011

1 nibble for hex 5=0101

1 nibble for hex 3=0011

1 nibble for hex 6=0110

now see calculations for sending 3 to another computer parallel....

03=00000011   data line D4=0 (hand shaking bit)
D7= 10011 111   busy =1 (received)
10011 111>> 3 = 00010011
Value extraction:
00010011 & 00001111  = 00000011 = 03
Data line D4 = 0 (send for verification)
D0=10011000     busy  = 1 (received and verified)


i hope u got it now.........do the same for next 3 nibbles.....

2011/11/11 CoooL <asad.coool786@gmail.com>

Any one have idea solution of cs609 then share and discuss wid me

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